Question:
Three circles of radii $a, b, c^{\prime \prime}(a
Correct Option: 1
Solution:
$A M^{2}=A C^{2}-M C^{2}$
$=(a+c)^{2}-(a-c)^{2}=4 a c$
$\Rightarrow A M^{2}=X Y^{2}=4 a c$
$\Rightarrow X Y=2 \sqrt{a c}$
Similarly, $Y Z=2 \sqrt{b a}$ and $X Z=2 \sqrt{b c}$
Then, $X Z=X Y+Y Z$
$\Rightarrow \quad 2 \sqrt{b c}=2 \sqrt{a c}+2 \sqrt{b a}$
$\Rightarrow \quad \frac{1}{\sqrt{a}}=\frac{1}{\sqrt{b}}+\frac{1}{\sqrt{c}}$