Question:
Three circles of radii a, b, c $(a
Correct Option: 1
Solution:
$\mathrm{AB}=\mathrm{AC}+\mathrm{CB}$
$\sqrt{(b+c)^{2}-(b-c)^{2}}$
$=\sqrt{(b+a)^{2}-(b-a)^{2}}+\sqrt{(a+c)^{2}-(a-c)^{2}}$
$\sqrt{b c}=\sqrt{a b}+\sqrt{a c}$
$\frac{1}{\sqrt{a}}=\frac{1}{\sqrt{c}}+\frac{1}{\sqrt{b}}$