The zeroes of the polynomial p(x)

(b) 0, 3

Let:

$p(x)=x^{2}-3 x$

Now, we have:

$p(x)=0 \Rightarrow x^{2}-3 x=0$

$\Rightarrow x(x-3)=0$

$\Rightarrow x=0$ and $x-3=0$

$\Rightarrow x=0$ and $x=3$