Question:
The Young’s modulus for steel is more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?
Solution:
Young’s modulus is given as:
Young's modulus $=\frac{\text { Tensile stress }}{\text { Longitudinal strain }}$
When the longitudinal strain is the same for both, steel will have a greater tensile stress.
$\frac{Y_{\text {steel }}}{Y_{\text {rubber }}}=\frac{\text { Stress }_{\text {steel }}}{\text { Stress_rubber }}$
$\frac{Y_{\text {steel }}}{Y_{\text {rubber }}}>1$
$\frac{\text { Stress_steel }}{\text { Stress }_{\text {rubber }}}>1 \Rightarrow$ Stress $_{\text {steel }}>$ Stress $_{\text {rubber }}$