Question:
The volume strength of $8.9 \mathrm{M} \mathrm{H}_{2} \mathrm{O}_{2}$ solution calculated at $273 \mathrm{~K}$ and $1 \mathrm{~atm}$ is_____________. $\left(\mathrm{R}=0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$ (rounded off to the nearest integer)
Solution:
(100)
Molarity of $\mathrm{H}_{2} \mathrm{O}_{2}$ solution $=\left\{\frac{\text { Volume strength }}{11.2}\right\}$
Volume strength $=8.9 \times 11.2=99.68 \mathrm{~V} \simeq 100 \mathrm{~V}$