Question:
The volume strength of $8.9 \mathrm{M} \mathrm{H}_{2} \mathrm{O}_{2}$ solution calculated at $273 \mathrm{~K}$ and $1 \mathrm{~atm}$ is $\left(\mathrm{R}=0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$ (rounded off to the nearest integer)
Solution:
Volume strength of $\mathrm{H}_{2} \mathrm{O}_{2}$ at $1 \mathrm{~atm}$
273 kelvin $=\mathrm{M} \times 11.2=8.9 \times 11.2=99.68$
Ans : 100
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