Question:
The velocity-displacement graph of a particle is shown in the figure.
The acceleration-displacement graph of the same particle is represented by :
Correct Option: , 3
Solution:
$\mathrm{V}=-\left(\frac{\mathrm{V}_{0}}{\mathrm{x}_{0}}\right) \mathrm{x}+\mathrm{v}_{0}$
$a=\frac{v d v}{d x}$
$a=\left[-\left(\frac{v_{0}}{x_{0}}\right) x+v_{0}\right]\left[-\frac{v_{0}}{x_{0}}\right]$
$\mathrm{a}=\left(\frac{\mathrm{v}_{0}}{\mathrm{x}_{0}}\right)^{2} \mathrm{x}-\frac{\mathrm{v}_{0}^{2}}{\mathrm{x}_{0}}$