Question:
The value of the polynomial $5 x-4 x^{2}+3$, when $x=-1$ is
(a)-6
(b) 6
(c) 2
(d) $-2$
Solution:
(a) Let $p(x)=5 x-4 x^{2}+3 \ldots$ (i)
On putting $x=-1$ in Eq. (i), we get
$p(-1)=5(-1)-4(-1)^{2}+3=-5-4+3=-6$
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