The value of $2 \sqrt{3}+\sqrt{3}$ is
(a) $2 \sqrt{6}$
(b) 6
(c) $3 \sqrt{3}$
(d) $4 \sqrt{6}$
$2 \sqrt{3}+\sqrt{3}=\sqrt{3}(2+1)=3 \sqrt{3}$
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