Question:
The value of (a + b)2 + (a – b)2 is
(a) 2a + 2b
(b) 2a – 2b
(c) 2a2 + 2b2
(d) 2a2 – 2b2
Solution:
(c) 2a2 + 2b2
(a + b)2 + (a – b)2 = (a2 + b2 + 2ab) + (a2 + b2 – 2ab)
= (a2 + a2) + (b2 + b2) + (2ab – 2ab)
= 2a2 + 2b2
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