Question: The value of (3x3 +9x2 + 27x) ÷ 3x is
(a) x2 +9 + 27x
(b) 3x3 +3x2 + 27x
(c) 3x3 +9x2 + 9
(d) x2 +3x + 9
Solution:
(d) x2 +3x + 9
The value of (3x3 +9x2 + 27x) ÷ 3x = (3x3 + 9x2 + 27x)/3x
Takeout 3x as common,
= 3x (x2 + 3x + 9)/3x
= x2 + 3x + 9
