Question:
The total number of electrons in all bonding molecular orbitals of $\mathrm{O}_{2}^{2-}$ is..........
(Round off to the nearest integer)
Solution:
M. O. Configuration of $\mathrm{O}_{2}^{2-}((18 \overline{\mathrm{e}})$
$\sigma 1 s^{2} \sigma 1 s^{2} \sigma 2 s^{2} \sigma 2 s^{2} \sigma 2 p_{z}^{2} \pi 2 p_{x}^{2}=\pi 2 p_{y}^{2}$
$\pi 2 p_{x}^{2}=\pi^{*} 2 p_{y}^{2}$
Total B.M.O electrons $=10$
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