The tangent to the curve

$y=x^{2}-5 x+5$

$\frac{\mathrm{dy}}{\mathrm{dx}}=2 \mathrm{x}-5=2 \Rightarrow \mathrm{x}=\frac{7}{2}$

at $\mathrm{x}=\frac{7}{2}, \mathrm{y}=\frac{-1}{4}$

Equation of tangent at $\left(\frac{7}{2}, \frac{-1}{4}\right)$ is $2 \mathrm{x}-\mathrm{y}-\frac{29}{4}=0$

Now check options

$x=\frac{1}{8}, y=-7$