Question:
The sum of two numbers is $\frac{-4}{3}$. If one of the numbers is $-5$, find the other.
Solution:
It is given that the sum of two numbers is $\frac{-4}{3}$, where one of the number $s$ is $-5$.
Let the other number be $x$.
$\therefore x+(-5)=\frac{-4}{3}$
$\Rightarrow x=\frac{-4}{3}-\left(\frac{-5}{1}\right)$
$\Rightarrow x=\frac{-4}{3}-\frac{-15}{3}$
$\Rightarrow x=\frac{-4-(-15)}{3}$
$\Rightarrow x=\frac{-4+15}{3}=\frac{11}{3}$