Question: The sum of the roots of the equation $x^{2}-6 x+2=0$ is
(a) 2
(b) −2
(c) 6
(d) −6
Solution:
(c) 6
Sum of the roots of the equation $x^{2}-6 x+2=0$ is
$\alpha+\beta=\frac{-b}{a}=\frac{-(-6)}{1}=6$, where $\alpha$ and $\beta$ are the roots of the equation.
