Question:
The sum of first 25 odd natural numbers is _________.
Solution:
Sum of for 25 odd numbers :-
Let S denote the sum of first 25 odd numbers
Here number are 1, 3, 5, 7, 9 --------- 49.
Here first term is 1
last term is 49
Common difference d is 2
n = 25
i. e Sum $=\frac{n}{2}\left(a+T_{n}\right)$
$=\frac{25}{2}(1+49)$
$=\frac{25 \times 50}{2}$
$=25 \times 25$
i.e sum of first 25 odd numbers = 625.