The standard Gibbs energy for the given cell reaction

Question:

The standard Gibbs energy for the given cell reaction in $\mathrm{kJ} \mathrm{mol}^{-1}$ at $298 \mathrm{~K}$ is :

$\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(\mathrm{aq}) \rightarrow \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})$

$\mathrm{E}^{\circ}=2 \mathrm{~V}$ at $298 \mathrm{~K}$

(Faraday's constant, $\mathrm{F}=96000 \mathrm{C} \mathrm{mol}^{-1}$ )

  1. $-384$

  2. $-192$

  3. 192

  4. 384


Correct Option: 1

Solution:

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