Question: The species that has a spin only magnetic moment of $5.9 \mathrm{BM}$, is -
$\mathrm{Ni}(\mathrm{CO})_{4}\left(\mathrm{~T}_{\mathrm{d}}\right)$
$\left[\mathrm{MnBr}_{4}\right]^{2}-\left(\mathrm{T}_{\mathrm{d}}\right)$
$\left[\mathrm{NiCl}_{4}\right]^{2}-\left(\mathrm{T}_{\mathrm{d}}\right)$
$\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}$ (square planar)
Correct Option: , 2
Solution:
(2) $\left[\mathrm{MnBr}_{4}\right]^{2}-\left(\mathrm{T}_{\mathrm{d}}\right)$
