The solubility of

Question:

The solubility of $\mathrm{AgCN}$ in a buffer solution of $\mathrm{pH}=3$ is $\mathrm{x}$. The value of $\mathrm{x}$ is:

[Assume: No cyano complex is formed; $\mathrm{K}_{\mathrm{sp}}(\mathrm{AgCN})$ $=2.2 \times 10^{-16}$ and $\mathrm{K}_{\mathrm{a}}(\mathrm{HCN})=6.2 \times 10^{-10}$ ]

  1. $0.625 \times 10^{-6}$

  2. $1.9 \times 10^{-5}$

  3. $2.2 \times 10^{-16}$

  4. $1.6 \times 10^{-6}$


Correct Option: , 2

Solution:

$\frac{\mathrm{K}_{\mathrm{sp}}}{\mathrm{Ka}}=\frac{\mathrm{s}^{2}}{\left(\mathrm{H}^{+}\right)} ; \quad \mathrm{s}=\sqrt{\frac{\mathrm{K}_{\mathrm{sp}}}{\mathrm{K}_{\mathrm{a}}}\left(\mathrm{H}^{+}\right)}$

$\mathrm{s}=\sqrt{\frac{2.2 \times 10^{-16}}{6.2 \times 10^{-10}} \times 10^{-3}}$

$\mathrm{s}=1.9 \times 10^{-5}$

Hence answer is $(2)$

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