The slant height of a bucket is 45 cm and the radii of its top and bottom are 28 cm and 7 cm, respectively.

(d) 4950 cm2
Let the radii of the top and bottom of the bucket be R and r and let its slant height be l.

Then, $R=28 \mathrm{~cm}, r=7 \mathrm{~cm}, l=45 \mathrm{~cm}$

Curved surface area of the bucket $=\pi l(R+r)$

$=\frac{22}{7} \times 45 \times(28+7) \mathrm{cm}^{2}$

$=4950 \mathrm{~cm}^{2}$

Hence, the curved surface area of the bucket is 4950 cm2.