Question:
The shape of the top surface of a table is trapezium. Its parallel sides are 1 m and 1.4 m and the perpendicular distance between them is 0.9 m. Find its area..png)
Solution:
Area of a trapezium $=\frac{1}{2} \times($ Sum of parallel sides $) \times($ Distance between them $)$
$=\left\{\frac{1}{2} \times(1+1.4) \times 0.9\right\} \mathrm{m}^{2}$
$=\left(\frac{1}{2} \times 2.4 \times 0.9\right) \mathrm{m}^{2}$
$=(1.2 \times 0.9) \mathrm{m}^{2}$
$=1.08 \mathrm{~m}^{2}$
Hence, the area of the top surface of the table is $1.08 \mathrm{~m}^{2}$.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.