Question:
The shape of the cross section of a canal is a trapezium. If the canal is 10 m wide at the top, 6 m wide at the bottom and the area of its cross section is 640 m2, find the depth of the canal.
Solution:
Area of the canal $=640 \mathrm{~m}^{2}$
Area of trapezium $=\frac{1}{2} \times($ Sum of parallel sides $) \times($ Distance between them $)$
$\Rightarrow 640=\frac{1}{2} \times(10+6) \times h$
$\Rightarrow \frac{1280}{16}=h$
$\Rightarrow h=80 \mathrm{~m}$
Therefore, the depth of the canal is 80 m.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.