The resistance of a conductivity cell with cell constant $1.14 \mathrm{~cm}^{-1}$, containing $0.001 \mathrm{M} \mathrm{KCl}$ at $298 \mathrm{~K}$ is $1500 \Omega$. The molar conductivity of $0.001 \mathrm{M} \mathrm{KCl}$
solution at $298 \mathrm{~K}$ in $\mathrm{S} \mathrm{cm}^{2} \mathrm{~mol}^{-1}$ is___________
(Integer answer)
$\mathrm{K}=\frac{1}{\mathrm{R}} \times y / \mathrm{A}=\left(\left(\frac{1}{1500}\right) \times 1.14\right) \mathrm{S} \mathrm{cm}^{-1}$
$\Rightarrow \wedge_{\mathrm{m}}=1000 \times \frac{\left(\frac{1.14}{1500}\right)}{0.001} \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
$=760 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
$\Rightarrow 760$
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