Question:
The ranges and heights for two projectiles projected with the same initial velocity at angles $42^{\circ}$ and $48^{\circ}$ with the horizontal are $\mathrm{R}_{1}, \mathrm{R}_{2}$ and $\mathrm{H}_{1}$, $\mathrm{H}_{2}$ respectively. Choose the correct option:
Correct Option: 2,
Solution:
Range $\mathrm{R}=\frac{\mathrm{u}^{2} \sin 2 \theta}{\mathrm{g}}$ and same for $\theta$ and $90-\theta$
So same for $42^{\circ}$ and $48^{\circ}$
Maximum height $\mathrm{H}=\frac{\mathrm{u}^{2} \sin ^{2} \theta}{2 \mathrm{~g}}$
$\mathrm{H}$ is high for higher $\theta$
So $\mathrm{H}$ for $48^{\circ}$ is higher than $\mathrm{H}$ for $42^{\circ}$
Option (2)