The radii of the circular ends of a solid frustum

The slant height of the frustum of a cone is l=10cm. The radii of the upper and lower circles of the bucket are r1 =33cm and r2 =27cm respectively.

The total surface area of the frustum of the cone is

$S_{1}=\pi\left(r_{1}+r_{2}\right) \times l+\pi r_{1}^{2}+\pi r_{2}^{2}$

$=\pi \times(33+27) \times 10+\pi \times 33^{2}+\pi \times 27^{2}$

$=600 \pi+1089 \pi+729 \pi$

$=7599.42 \mathrm{~cm}^{2}$

Hence total surface area is $7599.42 \mathrm{~cm}^{2}$