Question:
The product of two rational numbers is $\frac{-16}{9}$. If one of the numbers is $\frac{-4}{3}$, find the other.
Solution:
Let the number be $\mathrm{x}$.
Now,
$\mathrm{x} \times \frac{-4}{3}=\frac{-16}{9}$
$\Rightarrow \mathrm{x}=\frac{-16}{9} \div \frac{-4}{3}$
$\Rightarrow \mathrm{x}=\frac{-16}{9} \times \frac{3}{-4}$
$\Rightarrow \mathrm{x}=\frac{-16 \times 3}{9 \times(-4)}$
$\Rightarrow \mathrm{x}=\frac{48}{36}$
$\Rightarrow \mathrm{x}=\frac{4}{3}$