The product $2^{\frac{1}{4}} \cdot 4^{\frac{1}{16}} \cdot 8^{\frac{1}{48}} \cdot 16^{\frac{1}{128}}$
to $\infty$ is equal to :
$2^{\frac{1}{2}}$
$2^{\frac{1}{4}}$
2
1
Correct Option: 1
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