Question:
The $\mathrm{oH}$ of a sample of vinegar is 376 Calculate the concentration of hydrogen ion in it
Solution:
Given,
pH = 3.76
It is known that,
$\mathrm{pH}=-\log \left[\mathrm{H}^{+}\right]$
$\Rightarrow \log \left[\mathrm{H}^{+}\right]=-\mathrm{pH}$
$\Rightarrow\left[\mathrm{H}^{+}\right]=\operatorname{antilog}(-\mathrm{pH})$
$=\operatorname{antilog}(-3.76)$
$=1.74 \times 10^{-4} \mathrm{M}$
Hence, the concentration of hydrogen ion in the given sample of vinegar is $1.74 \times 10^{-4} \mathrm{M}$.