Question:
The period of oscillation of a simple pendulum is $T=2 \pi \sqrt{\frac{L}{g}}$. Measured value of $L$ is $20.0 \mathrm{~cm}$
known to $1 \mathrm{~mm}$ accuracy and time for 100 oscillations of the pendulum is found to be $90 \mathrm{~s}$ using a wrist watch of 1 s resolution. The accuracy in the determination of $g$ is :
Correct Option: , 4
Solution:
