Question:
The perimeter of a floor of a room is 30 m and its height is 3 m. Find the area of four walls of the room.
Solution:
Perimeter of the floor of the room $=30 \mathrm{~m}$
Height of the oom $=3 \mathrm{~m}$
Perimeter of a rectangle $=2 \times($ length $+$ breadth $)=30 \mathrm{~m}$
So, area of the four walls $=2 \times($ length $\times$ height $+$ breadth $\times$ height $)$
$=2 \times($ length $+$ breadth $) \times$ height
$=30 \times 3=90 \mathrm{~m}^{2}$