Question:
The parallel sides of a trapezium are 9.7 cm and 6.3 cm, and the distance between them is 6.5 cm. The area of the trapezium is
(a) 104 cm2
(b) 78 cm2
(c) 52 cm2
(d) 65 cm2
Solution:
(c) 52 cm2
Area of trapezium $=\frac{1}{2}$ (Sum of parallel sides) $\times$ Distance between them
$=\frac{1}{2} \times(9.7+6.3) \times 6.5$
$=8 \times 6.5$
$=52.0 \mathrm{~cm}^{2}$