The numbers 42, 43, 44, 44, (2x + 3), 45, 45, 46, 47 have been arranged in an ascending order and their median is 45.
Question:
The numbers 42, 43, 44, 44, (2x + 3), 45, 45, 46, 47 have been arranged in an ascending order and their median is 45. Find the value of x. Hence, find the mode of the above data.
Solution:
Arranging the given data in ascending order:
42, 43, 44, 44, (2x + 3), 45, 45, 46, 47
Number of terms = 9 (odd)
$\therefore$ Median $=\left(\frac{n+1}{2}\right)^{\text {th }}$ term
$\Rightarrow 45=\left(\frac{9+1}{2}\right)^{\text {th }}$ term
$\Rightarrow 45=(5)^{\text {th }}$ term
$\Rightarrow 45=2 x+3$
$\Rightarrow 2 x=45-3$
$\Rightarrow 2 x=42$
$\Rightarrow x=21$
Hence, the value of x is 21.
Arranging the given data in ascending order:
42, 43, 44, 44, 45, 45, 45, 46, 47
Here, 45 occurs maximum number of times.
∴ Mode = 45
Hence, the mode of the data is 45.