Question:
The number of terms in an A.P. whose first term is 10, last term is 50 and the sum of all terms is 300, is ___________.
Solution:
First term of A.P is given = 10
Last term of A.P is given = 50
Sum of all terms Sn = 300 (given)
Since sum of all terms $S_{n}=\frac{n \text { (First term+Last term) }}{2}$
i. e $300=n\left(\frac{10+50}{2}\right)^{2}$
i. e $300=n\left(\frac{60}{2}\right)$
i. e $300=n(30)$
i. e $n=10$
Hence, number of terms of an A.P is 10.