Question:
The number of geometrical isomers possible in triamminetrinitrocobalt (III) is $\mathrm{X}$ and in trioxalatochromate (III) is Y. Then the value of $\mathrm{X}+\mathrm{Y}$ is___________.
Solution:
Triamminetrinitrocobalt(III) $\rightarrow\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{3}\left(\mathrm{NH}_{3}\right)_{3}\right]$ trioxalatochromate(III) ion $\rightarrow\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ $\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{3}\left(\mathrm{NH}_{3}\right)_{3}\right]$
