Question: The negation of the statement
$\sim p \wedge(p \vee q)$ is :
(1) $\sim p \wedge q$
(2) $\mathrm{p} \wedge \sim \mathrm{q}$
(3) $\sim p \vee q$
(4) $\mathrm{p} \vee \sim \mathrm{q}$
Correct Option: , 4
Solution:
$\therefore \sim p \wedge(p \vee q) \equiv \mathrm{p} \vee \sim \mathrm{q}$
