Question: The moment of inertia of a uniform cylinder of length $\ell$ and radius $\mathrm{R}$ about its perpendicular bisector is I. What is the ratio $\ell / R$ such that the moment of inertia is minimum ?
1
$\frac{3}{\sqrt{2}}$
$\sqrt{\frac{3}{2}}$
$\frac{\sqrt{3}}{2}$
Correct Option: , 3
Solution:
