The mole fraction of a solvent in aqueous solution

Question:

The mole fraction of a solvent in aqueous solution of a solute is $0.8$. The molality (in mol kg-1) of the aqueous solution is

  1. $13.88 \times 10^{-1}$

  2. $13.88 \times 10^{-2}$

  3. $13.88$

  4. $13.88 \times 10^{-3}$

Correct Option: , 3

Solution:

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