Question: The mojor product of the following reaction is :
$\mathrm{CH}_{3} \mathrm{CD}(\mathrm{Cl}) \mathrm{CHD}$ (I)
$\mathrm{CH}_{3} \mathrm{CD}_{2} \mathrm{CH}(\mathrm{Cl})$ (I)
$\mathrm{CH}_{3} \mathrm{CD}(\mathrm{I}) \mathrm{CHD}(\mathrm{Cl})$
$\mathrm{CH}_{3} \mathrm{C}(\mathrm{I})(\mathrm{Cl}) \mathrm{CHD}_{2}$
Correct Option: , 4
Solution:
