Question:
The measure of one angle of a parallelogram is 70°. What are the measures of the remaining angles?
Solution:
Given that one angle of the parallelogram is $70^{\circ}$.
Since opposite angles have same value, if one is $70^{\circ}$, then the one directly opposite will also be $70^{\circ}$.
So, let one angle be $x^{\circ}$.
$\mathrm{x}^{\circ}+70^{\circ}=180^{\circ}$ (the sum of adjacent angles of a parallelogram is $180^{\circ}$ )
$\mathrm{x}^{\circ}=180^{\circ}-70^{\circ}$
$\mathrm{x}^{\circ}=110^{\circ}$
Thus, the remaining angles are $110^{\circ}, 110^{\circ}$ and $70^{\circ}$.