Question:
The mean of the marks scored by 50 students was found to be 39. Later on it was discovered that a score of 43 was misread as 23. Find the correct mean.
Solution:
Let the marks scored by 50 students be x1, x2,...x50.
Mean = 39
We know:
Mean $=\frac{\text { Sum of observa tions }}{\text { Number of observations }}$
Thus, we have:
$39=\frac{x_{1}+x_{2}+\ldots+x_{50}}{50}$
$\Rightarrow x$
$\Rightarrow x_{1}+x_{2}+\ldots+x_{50}=1950 \ldots \ldots$ (i)
Also, a score of 43 was misread as 23.
$\therefore$ New Mean $=\frac{\left(x_{1}+x_{2}+\ldots+x_{50}\right)-23+43}{50}$
$=\frac{1950-23+43}{50} \quad[$ using $(\mathrm{i})]$
$=\frac{1970}{50}$
$=39.4$