Question: The major product of the following reaction is :
$\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCO}_{2} \mathrm{CH}_{3} \stackrel{\mathrm{LiAlH}_{4}}{\longrightarrow}$
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CHO}$
$\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{2} \mathrm{OH}$
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{CH}_{3}$
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}$
Correct Option: , 2
Solution:
