Question: The locus of the foot of perpendicular drawn from the centre of the ellipse $x^{2}+3 y^{2}=6$ on any tangent to it is :-
$\left(x^{2}-y^{2}\right)^{2}=6 x^{2}+2 y^{2}$
$\left(x^{2}-y^{2}\right)^{2}=6 x^{2}-2 y^{2}$
$\left(x^{2}+y^{2}\right)^{2}=6 x^{2}+2 y^{2}$
$\left(x^{2}+y^{2}\right)^{2}=6 x^{2}-2 y^{2}$
Correct Option: , 3
Solution:
