Question:
The length of metallic wire is $l_{1}$ when tension in it is $T_{1}$. It is $l_{2}$ when the tension is $T_{2}$. The original length of the wire will be :
Correct Option: , 4
Solution:
(4)
From young's modulus relation $\left(\mathrm{y}=\frac{\frac{\mathrm{F}}{\mathrm{A}}}{\left(\frac{\Delta \mathrm{I}}{\mathrm{I}}\right)}\right)$
we can write for $1^{\text {st }}$ case
$\frac{T_{1}}{A}=\frac{y\left(\ell_{1}-\ell\right)}{\ell}$
we can write for $2^{\text {nd }}$ case
$\frac{T_{2}}{A}=\frac{y\left(\ell_{2}-\ell\right)}{\ell}$
$\frac{T_{1}}{T_{2}}=\frac{\ell_{1}-\ell}{\ell_{2}-\ell}$
$\mathrm{T}_{1} \ell_{2}-\mathrm{T}_{1} \ell=\mathrm{T}_{2} \ell_{1}-\mathrm{T}_{2} \ell$
$\frac{T_{2} l_{1}-T_{1} l_{2}}{T_{2}-T_{1}}=\ell$