Question.
The length, breadth and thickness of a rectangular sheet of metal are $4.234 \mathrm{~m}, 1.005 \mathrm{~m}$, and $2.01 \mathrm{~cm}$ respectively. Give the area and volume of the sheet to correct significant figures.
The length, breadth and thickness of a rectangular sheet of metal are $4.234 \mathrm{~m}, 1.005 \mathrm{~m}$, and $2.01 \mathrm{~cm}$ respectively. Give the area and volume of the sheet to correct significant figures.
solution:
Length of sheet, $I=4.234 \mathrm{~m}$
Breadth of sheet, $b=1.005 \mathrm{~m}$
Thickness of sheet, $h=2.01 \mathrm{~cm}=0.0201 \mathrm{~m}$
The given table lists the respective significant figures:
Hence, area and volume both must have least significant figures i.e., 3.
Surface area of the sheet $=2(l \times b+b \times h+h \times l)$
$=2(4.234 \times 1.005+1.005 \times 0.0201+0.0201 \times 4.234)$
$=2(4.25517+0.0202005+0.0851034)$
$=2 \times 4.36$
$=8.72 \mathrm{~m}^{2}$
Volume of the sheet = l × b × h
$=0.0855 \mathrm{~m}^{3}$
This number has only 3 significant figures i.e., 8, 5, and 5.
Length of sheet, $I=4.234 \mathrm{~m}$
Breadth of sheet, $b=1.005 \mathrm{~m}$
Thickness of sheet, $h=2.01 \mathrm{~cm}=0.0201 \mathrm{~m}$
The given table lists the respective significant figures:
Hence, area and volume both must have least significant figures i.e., 3.
Surface area of the sheet $=2(l \times b+b \times h+h \times l)$
$=2(4.234 \times 1.005+1.005 \times 0.0201+0.0201 \times 4.234)$
$=2(4.25517+0.0202005+0.0851034)$
$=2 \times 4.36$
$=8.72 \mathrm{~m}^{2}$
Volume of the sheet = l × b × h
$=0.0855 \mathrm{~m}^{3}$
This number has only 3 significant figures i.e., 8, 5, and 5.