Question:
The interaction energy of London forces between two particles is proportional to $\mathrm{r}^{\mathrm{x}}$, where $\mathrm{r}$ is the distance between the particles. The value of $x$ is :
Correct Option: , 3
Solution:
For london dispersion forces.
$E \propto \frac{1}{r^{6}}$
Hence $x=-6$