Question: The image of the line $\frac{x-1}{3}=\frac{y-3}{1}=\frac{z-4}{-5}$ in the plane $2 x-y+z+3=0$ is the line:
$\frac{\mathrm{x}+3}{3}=\frac{\mathrm{y}-5}{1}=\frac{\mathrm{z}-2}{-5}$
$\frac{x+3}{-3}=\frac{y-5}{-1}=\frac{z+2}{5}$
$\frac{x-3}{3}=\frac{y+5}{1}=\frac{z-2}{-5}$
$\frac{x-3}{-3}=\frac{y+5}{-1}=\frac{z-2}{5}$
Correct Option: 1
Solution:
