Question:
The hypotenuse of a right angled triangle with its legs of lengths 3x x 4x is
(a) 5X
(b )7x
(c) 16x
(d) 25x
Solution:
(a) Given, lengths of the legs of right angled triangle are $3 x$ and $4 x$.
Now, hypotenuse $=\sqrt{(3 x)^{2}+(4 x)^{2}}$ [using Pythagoras theorem]
$=\sqrt{9 x^{2}+16 x^{2}}$
$=\sqrt{25 x^{2}}=5 x$