Question: The hybridisation of orbitals of $\mathrm{N}$ atom in $\mathrm{NO}_{3}^{-}, \mathrm{NO}_{2}^{+}$and $\mathrm{NH}_{4}^{+}$are respectively:-
$s p, s p^{3}, s p^{2}$
$s p^{2}, s p^{3}, s p$
$s p, s p^{2}, s p^{3}$
$\mathrm{sp}^{2}, \mathrm{sp}, \mathrm{sp}^{3}$
Correct Option: , 4
Solution: