Question:
The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point
(a) (2,0)
(b) (0, 3)
(c)(3,0)
(d) (0, 2)
Solution:
(d) Since, the graph of linear equation 2x + 3y = 6 cuts the Y-axis.
So, we put x = 0 in the given equation 2x+ 3y = 6, we get
2 x 0+ 3y = 6 => 3y = 6
y=2.
Hence, at the point (0, 2), the given linear equation cuts the Y-axis.