The following observations have been arranged in ascending order.

Solution:

It can be observed that the total number of observations in the given data is 10 (even number). Therefore, the median of this data will be the mean of $\frac{10}{2}$ i.e., $5^{\text {th }}$ and $\frac{10}{2}+1$ i.e., $6^{\text {th }}$ observation.

Therefore, median of data $=\frac{5^{\text {th }} \text { observation }+6^{\text {th }} \text { observation }}{2}$

$\Rightarrow 63=\frac{x+x+2}{2}$

$\Rightarrow 63=\frac{2 x+2}{2}$

$\Rightarrow 63=x+1$

$\Rightarrow x=62$